The steps to predict the population of a place in the years to come.

Published on: **Mar 4, 2016**

Source: www.slideshare.net

- 1. Population Predictor By: Mikayla Kopp
- 2. Intro To Population Predictor• To begin to predict a population you must ﬁrst get your numbers of previous years. In this project I used the years 1850, 1900, 1950, 1960, 1980, 1990, 2000 and 2010. We used all of these numbers to predict the year 2060
- 3. GraphYears and population Pick two points that best represent your population growth
- 4. Work Point One:• First you pick two (110, 45,684,000) points that best Point Two: represent your (130, 53, 880,000) growth.• The you plug the two points into the After plugging it in I got Slope equation. the answer 409, 800
- 5. Work• You then take your ﬁrst point and plug When plugging it into Point Slope Formula the it into Point Slope answer I got was 606,000 Form.• Your Slope answer is M and your Point When plugging into Slope answer is Y=Mx + B I got your B.. Plug into Y=409,800x+606,000 Y=Mx+B
- 6. Finishing up your work• Solve your 409,800(210)+606,000- equation by 860,580,000+606,000= placing you 861,186,000 number of years in the place of X Y=861,186,000 Population Prediction of france in 2060 is 861,186,000
- 7. Intro• Another way to predict your future population is to plug it into a quadratic equation.
- 8. Work• Choose three points Points: from your chart on (X1,Y1)=(0,36) slide three. Round (X2,Y2)=(50,41) the to the nearest (X3,Y3)=(100,42) millionth.• First plug in your ﬁrst point into the 36=ao2+bo+c equation c=36 Y1+ax12+bx1+c
- 9. Work• Then plug in C to 41=a(50)+b(50)+36 the equation and solve for A plug in your next A=-0.008 set of points.• Now that you have 42=a(100)2+b(100)+c a and c use B=-0.0292 elmination to ﬁnd your b
- 10. More Work• After you have found all of your points plug your numbers into Y=Ax 2+Bx+C. The answer is what you get after you plug in everything and you plug in one of your three points into X and Y.
- 11. Intro• This next equation that we will solve for will give us a log graph. You will need two points.
- 12. Graph
- 13. Work• The equation that you will need for this is Y=abx• Then plug X and 41=ab50 and 42=ab100 Y into the equation. You should have two equations so you can plug in both points.
- 14. Work• After you have 41b50/=ab50/b50 your problem 41/b100=ab 100 /b100 divide b and your exponent on both 41/b50=a and 42/b100=a sides of each equation• Then place A in the place of A 41/b50=42/b100
- 15. • Then Cross Answer= Multiply 41b100 =42b 50• Then divide by b50 41b50=42• Divide 41 on each 41b50/41=42/41 side b50=1.0243• Get rid of the exponent 50 b=1.0004803
- 16. Work• Now plug in b into the equation and solve 41=a(1.0004803)50 41/1.0242998=• And then after a(1.0242998)/ plug in your 1.0242888 points to check a=40.02734 your math. You got it right if it is close to 41